Optimal. Leaf size=134 \[ \frac {i f \text {Li}_2\left (-e^{i (c+d x)}\right )}{a d^2}-\frac {i f \text {Li}_2\left (e^{i (c+d x)}\right )}{a d^2}-\frac {2 f \log \left (\sin \left (\frac {c}{2}+\frac {d x}{2}+\frac {\pi }{4}\right )\right )}{a d^2}+\frac {(e+f x) \cot \left (\frac {c}{2}+\frac {d x}{2}+\frac {\pi }{4}\right )}{a d}-\frac {2 (e+f x) \tanh ^{-1}\left (e^{i (c+d x)}\right )}{a d} \]
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Rubi [A] time = 0.16, antiderivative size = 134, normalized size of antiderivative = 1.00, number of steps used = 9, number of rules used = 7, integrand size = 24, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.292, Rules used = {4535, 4183, 2279, 2391, 3318, 4184, 3475} \[ \frac {i f \text {PolyLog}\left (2,-e^{i (c+d x)}\right )}{a d^2}-\frac {i f \text {PolyLog}\left (2,e^{i (c+d x)}\right )}{a d^2}-\frac {2 f \log \left (\sin \left (\frac {c}{2}+\frac {d x}{2}+\frac {\pi }{4}\right )\right )}{a d^2}+\frac {(e+f x) \cot \left (\frac {c}{2}+\frac {d x}{2}+\frac {\pi }{4}\right )}{a d}-\frac {2 (e+f x) \tanh ^{-1}\left (e^{i (c+d x)}\right )}{a d} \]
Antiderivative was successfully verified.
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Rule 2279
Rule 2391
Rule 3318
Rule 3475
Rule 4183
Rule 4184
Rule 4535
Rubi steps
\begin {align*} \int \frac {(e+f x) \csc (c+d x)}{a+a \sin (c+d x)} \, dx &=\frac {\int (e+f x) \csc (c+d x) \, dx}{a}-\int \frac {e+f x}{a+a \sin (c+d x)} \, dx\\ &=-\frac {2 (e+f x) \tanh ^{-1}\left (e^{i (c+d x)}\right )}{a d}-\frac {\int (e+f x) \csc ^2\left (\frac {1}{2} \left (c+\frac {\pi }{2}\right )+\frac {d x}{2}\right ) \, dx}{2 a}-\frac {f \int \log \left (1-e^{i (c+d x)}\right ) \, dx}{a d}+\frac {f \int \log \left (1+e^{i (c+d x)}\right ) \, dx}{a d}\\ &=-\frac {2 (e+f x) \tanh ^{-1}\left (e^{i (c+d x)}\right )}{a d}+\frac {(e+f x) \cot \left (\frac {c}{2}+\frac {\pi }{4}+\frac {d x}{2}\right )}{a d}+\frac {(i f) \operatorname {Subst}\left (\int \frac {\log (1-x)}{x} \, dx,x,e^{i (c+d x)}\right )}{a d^2}-\frac {(i f) \operatorname {Subst}\left (\int \frac {\log (1+x)}{x} \, dx,x,e^{i (c+d x)}\right )}{a d^2}-\frac {f \int \cot \left (\frac {c}{2}+\frac {\pi }{4}+\frac {d x}{2}\right ) \, dx}{a d}\\ &=-\frac {2 (e+f x) \tanh ^{-1}\left (e^{i (c+d x)}\right )}{a d}+\frac {(e+f x) \cot \left (\frac {c}{2}+\frac {\pi }{4}+\frac {d x}{2}\right )}{a d}-\frac {2 f \log \left (\sin \left (\frac {c}{2}+\frac {\pi }{4}+\frac {d x}{2}\right )\right )}{a d^2}+\frac {i f \text {Li}_2\left (-e^{i (c+d x)}\right )}{a d^2}-\frac {i f \text {Li}_2\left (e^{i (c+d x)}\right )}{a d^2}\\ \end {align*}
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Mathematica [B] time = 1.10, size = 300, normalized size = 2.24 \[ \frac {\left (\sin \left (\frac {1}{2} (c+d x)\right )+\cos \left (\frac {1}{2} (c+d x)\right )\right ) \left (-2 d (e+f x) \sin \left (\frac {1}{2} (c+d x)\right )+d e \log \left (\tan \left (\frac {1}{2} (c+d x)\right )\right ) \left (\sin \left (\frac {1}{2} (c+d x)\right )+\cos \left (\frac {1}{2} (c+d x)\right )\right )+f \left (i \left (\text {Li}_2\left (-e^{i (c+d x)}\right )-\text {Li}_2\left (e^{i (c+d x)}\right )\right )+(c+d x) \left (\log \left (1-e^{i (c+d x)}\right )-\log \left (1+e^{i (c+d x)}\right )\right )\right ) \left (\sin \left (\frac {1}{2} (c+d x)\right )+\cos \left (\frac {1}{2} (c+d x)\right )\right )+f (c+d x) \left (\sin \left (\frac {1}{2} (c+d x)\right )+\cos \left (\frac {1}{2} (c+d x)\right )\right )-2 f \left (\sin \left (\frac {1}{2} (c+d x)\right )+\cos \left (\frac {1}{2} (c+d x)\right )\right ) \log \left (\sin \left (\frac {1}{2} (c+d x)\right )+\cos \left (\frac {1}{2} (c+d x)\right )\right )-c f \log \left (\tan \left (\frac {1}{2} (c+d x)\right )\right ) \left (\sin \left (\frac {1}{2} (c+d x)\right )+\cos \left (\frac {1}{2} (c+d x)\right )\right )\right )}{a d^2 (\sin (c+d x)+1)} \]
Antiderivative was successfully verified.
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fricas [B] time = 0.54, size = 609, normalized size = 4.54 \[ \frac {2 \, d f x + 2 \, d e + 2 \, {\left (d f x + d e\right )} \cos \left (d x + c\right ) + {\left (-i \, f \cos \left (d x + c\right ) - i \, f \sin \left (d x + c\right ) - i \, f\right )} {\rm Li}_2\left (\cos \left (d x + c\right ) + i \, \sin \left (d x + c\right )\right ) + {\left (i \, f \cos \left (d x + c\right ) + i \, f \sin \left (d x + c\right ) + i \, f\right )} {\rm Li}_2\left (\cos \left (d x + c\right ) - i \, \sin \left (d x + c\right )\right ) + {\left (-i \, f \cos \left (d x + c\right ) - i \, f \sin \left (d x + c\right ) - i \, f\right )} {\rm Li}_2\left (-\cos \left (d x + c\right ) + i \, \sin \left (d x + c\right )\right ) + {\left (i \, f \cos \left (d x + c\right ) + i \, f \sin \left (d x + c\right ) + i \, f\right )} {\rm Li}_2\left (-\cos \left (d x + c\right ) - i \, \sin \left (d x + c\right )\right ) - {\left (d f x + d e + {\left (d f x + d e\right )} \cos \left (d x + c\right ) + {\left (d f x + d e\right )} \sin \left (d x + c\right )\right )} \log \left (\cos \left (d x + c\right ) + i \, \sin \left (d x + c\right ) + 1\right ) - {\left (d f x + d e + {\left (d f x + d e\right )} \cos \left (d x + c\right ) + {\left (d f x + d e\right )} \sin \left (d x + c\right )\right )} \log \left (\cos \left (d x + c\right ) - i \, \sin \left (d x + c\right ) + 1\right ) + {\left (d e - c f + {\left (d e - c f\right )} \cos \left (d x + c\right ) + {\left (d e - c f\right )} \sin \left (d x + c\right )\right )} \log \left (-\frac {1}{2} \, \cos \left (d x + c\right ) + \frac {1}{2} i \, \sin \left (d x + c\right ) + \frac {1}{2}\right ) + {\left (d e - c f + {\left (d e - c f\right )} \cos \left (d x + c\right ) + {\left (d e - c f\right )} \sin \left (d x + c\right )\right )} \log \left (-\frac {1}{2} \, \cos \left (d x + c\right ) - \frac {1}{2} i \, \sin \left (d x + c\right ) + \frac {1}{2}\right ) + {\left (d f x + c f + {\left (d f x + c f\right )} \cos \left (d x + c\right ) + {\left (d f x + c f\right )} \sin \left (d x + c\right )\right )} \log \left (-\cos \left (d x + c\right ) + i \, \sin \left (d x + c\right ) + 1\right ) + {\left (d f x + c f + {\left (d f x + c f\right )} \cos \left (d x + c\right ) + {\left (d f x + c f\right )} \sin \left (d x + c\right )\right )} \log \left (-\cos \left (d x + c\right ) - i \, \sin \left (d x + c\right ) + 1\right ) - 2 \, {\left (f \cos \left (d x + c\right ) + f \sin \left (d x + c\right ) + f\right )} \log \left (\sin \left (d x + c\right ) + 1\right ) - 2 \, {\left (d f x + d e\right )} \sin \left (d x + c\right )}{2 \, {\left (a d^{2} \cos \left (d x + c\right ) + a d^{2} \sin \left (d x + c\right ) + a d^{2}\right )}} \]
Verification of antiderivative is not currently implemented for this CAS.
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giac [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {{\left (f x + e\right )} \csc \left (d x + c\right )}{a \sin \left (d x + c\right ) + a}\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
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maple [B] time = 0.24, size = 245, normalized size = 1.83 \[ \frac {2 f x +2 e}{d a \left ({\mathrm e}^{i \left (d x +c \right )}+i\right )}-\frac {e \ln \left ({\mathrm e}^{i \left (d x +c \right )}+1\right )}{a d}+\frac {e \ln \left ({\mathrm e}^{i \left (d x +c \right )}-1\right )}{a d}-\frac {f c \ln \left ({\mathrm e}^{i \left (d x +c \right )}-1\right )}{a \,d^{2}}-\frac {i f \polylog \left (2, {\mathrm e}^{i \left (d x +c \right )}\right )}{a \,d^{2}}+\frac {i f \polylog \left (2, -{\mathrm e}^{i \left (d x +c \right )}\right )}{a \,d^{2}}-\frac {2 f \ln \left ({\mathrm e}^{i \left (d x +c \right )}+i\right )}{a \,d^{2}}+\frac {2 f \ln \left ({\mathrm e}^{i \left (d x +c \right )}\right )}{a \,d^{2}}-\frac {\ln \left ({\mathrm e}^{i \left (d x +c \right )}+1\right ) f x}{a d}+\frac {\ln \left (1-{\mathrm e}^{i \left (d x +c \right )}\right ) f x}{a d}+\frac {\ln \left (1-{\mathrm e}^{i \left (d x +c \right )}\right ) c f}{a \,d^{2}} \]
Verification of antiderivative is not currently implemented for this CAS.
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maxima [B] time = 0.91, size = 517, normalized size = 3.86 \[ \frac {4 \, d f x \cos \left (d x + c\right ) + 4 i \, d f x \sin \left (d x + c\right ) - 4 i \, d e - {\left (4 \, f \cos \left (d x + c\right ) + 4 i \, f \sin \left (d x + c\right ) + 4 i \, f\right )} \arctan \left (\cos \relax (c) + \sin \left (d x\right ), \cos \left (d x\right ) + \sin \relax (c)\right ) - {\left (2 i \, d f x + 2 i \, d e + 2 \, {\left (d f x + d e\right )} \cos \left (d x + c\right ) + {\left (2 i \, d f x + 2 i \, d e\right )} \sin \left (d x + c\right )\right )} \arctan \left (\sin \left (d x + c\right ), \cos \left (d x + c\right ) + 1\right ) + {\left (2 \, d e \cos \left (d x + c\right ) + 2 i \, d e \sin \left (d x + c\right ) + 2 i \, d e\right )} \arctan \left (\sin \left (d x + c\right ), \cos \left (d x + c\right ) - 1\right ) - {\left (2 \, d f x \cos \left (d x + c\right ) + 2 i \, d f x \sin \left (d x + c\right ) + 2 i \, d f x\right )} \arctan \left (\sin \left (d x + c\right ), -\cos \left (d x + c\right ) + 1\right ) + {\left (2 \, f \cos \left (d x + c\right ) + 2 i \, f \sin \left (d x + c\right ) + 2 i \, f\right )} {\rm Li}_2\left (-e^{\left (i \, d x + i \, c\right )}\right ) - {\left (2 \, f \cos \left (d x + c\right ) + 2 i \, f \sin \left (d x + c\right ) + 2 i \, f\right )} {\rm Li}_2\left (e^{\left (i \, d x + i \, c\right )}\right ) - {\left (d f x + d e + {\left (-i \, d f x - i \, d e\right )} \cos \left (d x + c\right ) + {\left (d f x + d e\right )} \sin \left (d x + c\right )\right )} \log \left (\cos \left (d x + c\right )^{2} + \sin \left (d x + c\right )^{2} + 2 \, \cos \left (d x + c\right ) + 1\right ) + {\left (d f x + d e - {\left (i \, d f x + i \, d e\right )} \cos \left (d x + c\right ) + {\left (d f x + d e\right )} \sin \left (d x + c\right )\right )} \log \left (\cos \left (d x + c\right )^{2} + \sin \left (d x + c\right )^{2} - 2 \, \cos \left (d x + c\right ) + 1\right ) + 2 \, {\left (i \, f \cos \left (d x + c\right ) - f \sin \left (d x + c\right ) - f\right )} \log \left (\cos \left (d x\right )^{2} + \cos \relax (c)^{2} + 2 \, \cos \relax (c) \sin \left (d x\right ) + \sin \left (d x\right )^{2} + 2 \, \cos \left (d x\right ) \sin \relax (c) + \sin \relax (c)^{2}\right )}{-2 i \, a d^{2} \cos \left (d x + c\right ) + 2 \, a d^{2} \sin \left (d x + c\right ) + 2 \, a d^{2}} \]
Verification of antiderivative is not currently implemented for this CAS.
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mupad [F(-1)] time = 0.00, size = -1, normalized size = -0.01 \[ \text {Hanged} \]
Verification of antiderivative is not currently implemented for this CAS.
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sympy [F] time = 0.00, size = 0, normalized size = 0.00 \[ \frac {\int \frac {e \csc {\left (c + d x \right )}}{\sin {\left (c + d x \right )} + 1}\, dx + \int \frac {f x \csc {\left (c + d x \right )}}{\sin {\left (c + d x \right )} + 1}\, dx}{a} \]
Verification of antiderivative is not currently implemented for this CAS.
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